Ortega method


Goal is this time to make 1 face instead of 1 complete layer. So take white for example and put all the white cubies on 1 face, not looking at there permutation. The result is that the last step is drammaticaly faster.

Step 1, make a face


Simply make 1 correct orienten but not permutated face. This step is easy, but hard to do it the optimal way.

Step 2, orientate bottom corners.



Now, when you have 1 face, orient the bottom corners with these algs.
See which case you have (if the cubies are already correctly orientated go to step 3) and perform the alg.

Note: you see that the first layer is completely solved, this is not necessary, but it's just that I'm lazy and used the images from the page where you do make one complete layer.















(R'U'RU')(R'U2R)

(R'U2)(RUR'UR)

y2 FR'F'RURU'R'

y RUR'U'R'FRF'

(FURU'R'F')

FRUR'U'RUR'U'F'

R2 U2 R U2 R2

Step 3, both layers


This step is pretty easy, you can learn the first 6 cases (including solved case, but for optimization for this step, learn to do case 1, 4 and 5 from different angles. I gave 2 algs for other angles but there are 3 more I use.
Recognition:
I got a lot of people stuck on saying: 'I have a case which is not on your site' this is because mostly they'll have case 4 as stated here. I updated the image to show the 2 bars don't have to match on colour. This is the basic thing for recognition of the cases. Look for pairs of connected pieces in U and D layer, they don't have to match. So if there is only one pair you'd have a case like #5/#8. 2 bars and you have #4/#7. No bars at all and you'll have #6. Of course you can recognize the cases where there is one layer correct already.

















(RU2R'U')(RU2)(L'UR'U'L')

RU'R'U'F2U'RUR'DR2

Already solved! :)

R2UR2' (U2 + y') R2UR2'

LD'L F2 L'DL'

R2F2R2

R2UF2U2R2UR2'

RU'R F2 R'UR'

Done!!congratulations!!